Re: Ambiguous constructor call

Hi to all,
I'm working on a smart pointer implementation and I'm trying to get
automatic type conversion between different pointer types. I stumbled
upon something weird (at least for me) I summarized it in the code
below. I was expecting both things at the end to work or not work at
all....
Any insight?
Thanks in advance,
Francesco

#include <iostream>

class A;

//

class B
{
public:

    B() { std::cout << "B()\n"; }

    B( B const & ) { std::cout << "B( B const & )\n"; }

    ~B() { std::cout << "~B()\n"; }

    B & operator=( B const & ) { std::cout << "B & operator=( B const & )
\n"; return *this; }

    template< typename T >
    operator T() const;
};

//

class A
{
public:

    A() { std::cout << "A()\n"; }

    explicit A( int ) { std::cout << "A( int )\n"; }

    A( A const & ) { std::cout << "A( A const & )\n"; }

    ~A() { std::cout << "~A()\n"; }

    A & operator=( A const & ) { std::cout << "A & operator=( A const & )
\n"; return *this; }
};

//

template< typename T >
B::operator T() const { std::cout << "B::operator T() const\n";
return T(); }

//

int main( )
{
    B obj001;
    A obj002 = obj001; // this works
    //A obj003( obj001 ); // this is ambiguous
}