Re: int to char problem ?
bushido wrote:
#include<iostream>
#include<vector>
#include<string>
using namespace std;
class Stack
{
public :
Stack();
void push(char&);
void push(const char&);
void pop();
char getpop();
A better name would be 'top'.
void output();
private:
vector<char> _vector;
int topOfStack;
Why is it 'int'?
};
Stack::Stack():topOfStack(-1){}
void Stack::push(char &x)
{
topOfStack++;
Why do you need this?
_vector.push_back(x);
}
void Stack::pop()
{
topOfStack--;
Why do you need this? You can change the size of the vector.
}
char Stack::getpop()
{
return _vector[topOfStack--];
You can simply do _vector.back();
}
void Stack::output()
{
for(int i = topOfStack-1; i != -1 ; i--)
{
cout<<"item "<<i<<"= "<<_vector[i]<<endl;
}
Use _vector.size() instead of 'topOfStack'.
}
int main()
{
string _str;
cin>>_str;
Stack _stack;
for(int i=0 ;i != _str.size(); i++)
{
if((_str[i] != '+') && (_str[i] != '*'))
{
_stack.push(_str[i]);
So, you push every character from the string into the stack until
you meet a plus or an asterisk.
}
else if(_str[i] == '+')
{
int temp;
temp = _stack.getpop() + _stack.getpop();
When you add '5' and '6', what are you going to get? Write a simple
program:
#include <iostream>
int main() {
std::cout << "'5' + '6' is " << '5'+'6' << std::endl;
}
what do you get? Why?
char ctemp = (char)temp;
_stack.push(ctemp);
}
else if(_str[i] == '*')
{
int temp;
temp = _stack.getpop() * _stack.getpop();
char ctemp = (char)temp;
_stack.push(ctemp);
}
}
cout<<endl;
_stack.output();
return 0;
}
I have problem in line
Huh?
else if(_str[i] == '+')
{
int temp;
temp = _stack.getpop() + _stack.getpop();
char ctemp = (char)temp;
_stack.push(ctemp);
}
else if(_str[i] == '*')
{
int temp;
temp = _stack.getpop() * _stack.getpop();
char ctemp = (char)temp;
_stack.push(ctemp);
}
b'coz ex. 56+
5 => 53
6 => 54
sum is 107 => k but i want 11 not k and push in vector is 11 plese
help.
You probably need to convert the char you're about to insert into its
"meaning". '5' you need to convert to value 5. '6' to value 6. YOu
can do it by subtracting '0' from the char.
V
--
Please remove capital 'A's when replying by e-mail
I do not respond to top-posted replies, please don't ask