Re: tr1::array initializater syntax

From:
Pete Becker <pete@versatilecoding.com>
Newsgroups:
comp.lang.c++
Date:
Thu, 14 Feb 2008 17:56:09 -0500
Message-ID:
<2008021417560950073-pete@versatilecodingcom>
On 2008-02-14 16:16:27 -0500, "Victor Bazarov" <v.Abazarov@comAcast.net> said:

Jeff Schwab wrote:

The latest GCC (4.2.3) gives a warning if a tr1::array is initialized
with the traditional syntax:

#include <iostream>
#include <tr1/array>

int main() {
std::tr1::array<int, 35> a = { 0 };
std::cout << a[4] << '\n';
}

g++ -ansi -pedantic -Wall main.cc -o main
main.cc: In function 'int main()':
main.cc:5: warning: missing braces around initializer for 'int
[35]'
Is this the expected behavior? What's the short, static way to
initialize a tr1::array of arbitrary size?


Since 'std::tr1::array' has the actual array as the 'elems' member,
you need to take your zero in curly braces:

    std::tr1::array<int, 35> a = { {0} };

That's what the compiler is telling you, BTW.


Well, it's not saying that you "need to" put in the unnecessary braces.
All it's doing is whining about some compiler writer's notion of good
style.

--
  Pete
Roundhouse Consulting, Ltd. (www.versatilecoding.com) Author of "The
Standard C++ Library Extensions: a Tutorial and Reference
(www.petebecker.com/tr1book)

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