Re: Generic iterator declaration
Hansel Stroem wrote:
Is this legitimate STL code ? Compiler seems not to like the iterator ...
No, it's not. It's missing a keyword or two.
template <typename Tn>
ostream& operator<<(ostream& out, vector<Tn> VV)
You should look into passing the vector by a reference to const:
... (ostream& out, vector<Tn> const& VV)
{
for ( vector<Tn>::iterator it = VV.begin(); it != VV.end(); ++it )
Has to be
for ( typename vector<Tn>::iterator it = ...
(or, if you decide to pass the vector by a const ref,
for ( typename vector<Tn>::const_iterator it =
{
out << (*it);
}
return out << std::endl;
}
%icc BS.cc
BS.cc(151): error: expected a ";"
for ( vector<Tn>::iterator it = VV.begin(); it != VV.end(); ++it )
^
BS.cc(151): error: identifier "it" is undefined
for ( vector<Tn>::iterator it = VV.begin(); it != VV.end(); ++it )
^
compilation aborted for BS.cc (code 2)
V
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