Re: Call a member function only if it exists in VC++ 9

From:
Maxim Yegorushkin <maxim.yegorushkin@gmail.com>
Newsgroups:
comp.lang.c++.moderated
Date:
Thu, 30 Oct 2008 16:14:02 CST
Message-ID:
<62518a1d-4310-4600-9d81-3d876b839156@v28g2000hsv.googlegroups.com>
On Oct 30, 12:47 am, steinb...@gmx.com wrote:

Hello,

I need to get this thing to work under MSVC++ 9.0:
-----------------
found here:http://groups.google.de/group/comp.lang.c++.moderated/browse_thread/t...

#include <iostream>
template<class T> struct has_member_f;

template<class R, class C>
class has_member_f<R C::*> {
private:
      template<R C::*> struct helper;
      template<class T> static char check(helper<&T::f>*);
      template<class T> static char (& check(...))[2];
public:
      static const bool value = (sizeof(check<C>(0)) ==
sizeof(char));

};

namespace boost { // no dependency of boost
template <bool B, class T = void>
struct enable_if_c {
      typedef T type;

};

template <>
struct enable_if_c<false, void> {};

} // namespace boost

void f() {
      std::cout << "::f()" << std::endl;

}

struct caller {
      template <class T>
      static void f(
          T& t,
          typename boost::enable_if_c<
              has_member_f<void (T::*)()>::value
          >::type* = 0) {
          t.f();
      }
      template <class T>
      static void f(
          T& t,
          typename boost::enable_if_c<
              !has_member_f<void (T::*)()>::value
          >::type* = 0) {
          ::f();
      }

};

// client code below
struct A { };
struct B {
      void f() {
          std::cout << "B::f" << std::endl;
      }

};

int main() {
      std::cout
          << has_member_f<void (A::*)()>::value << '\n'
          << has_member_f<void (B::*)()>::value << std::endl;
      A a;
      caller::f(a);
      B b;
      caller::f(b);}

-----------------

This is meant to call a member function only if it's defined.
Otherwise it calls the default behavior. The thing is, this behaves
fine with gcc 4, but not with VC++ 9.0.

Output GCC4:
------------
0
1
::f()
B::f

Output VC9:
-----------
0
0
::f()
::f()

VC9 supports partial specialized templates, (http://msdn.microsoft.com/
en-us/library/3967w96f.aspx), but I didn't get it to work as
expected...

Anyone any ideas?


I tried your code with M$VC 2005 and its output was similar to the
output of gcc 4.

The only thing that comes to my mind is to simplify the code a bit. I
don't have M$ VC 9 to check though.

Here is a version that uses overloading instead of enable_if along
with some other simplifications:

#include <iostream>

template<class T>
class has_member_f
{
private:
     template<void(T::*)()> struct helper;

     template<class U>
     static char check(U*, helper<&U::f>* = 0);
     static char(&check(...))[2];

public:
     static const bool value = (sizeof(check(static_cast<T*>(0))) ==
sizeof(char));
};

void f()
{
     std::cout << "::f()" << std::endl;
}

template<bool> struct bool_ {}; // boost::mpl::bool_

template<class T>
void do_invoke_f(T&, bool_<false>)
{
     ::f();
}

template<class T>
void do_invoke_f(T& t, bool_<true>)
{
     t.f();
}

template<class T>
void invoke_f(T& t)
{
     do_invoke_f(t, bool_<has_member_f<T>::value>());
}

// client code below
struct A {};
struct B {
     void f() {
         std::cout << "B::f" << std::endl;
     }
};

int main() {
     std::cout
         << has_member_f<A>::value << '\n'
         << has_member_f<B>::value << '\n';
     A a;
     invoke_f(a);
     B b;
     invoke_f(b);
}

--
Max

      [ See http://www.gotw.ca/resources/clcm.htm for info about ]
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