Re: cout << vector<string>

From:
James Kanze <james.kanze@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Mon, 10 Nov 2008 02:22:45 -0800 (PST)
Message-ID:
<f753a8a0-5205-4809-821c-2ec23864f588@o40g2000prn.googlegroups.com>
On Nov 10, 10:19 am, Maxim Yegorushkin <maxim.yegorush...@gmail.com>
wrote:

On Nov 7, 12:17 pm, Pete Becker <p...@versatilecoding.com> wrote:

On 2008-11-07 06:03:15 -0500, Maxim Yegorushkin
<maxim.yegorush...@gmail.com> said:

The example probably assumes there is an overloaded
operator<<() for std::ostream and std::vector<>, something
like this:

    #include <ostream>
    #include <iterator>
    #include <algorithm>

    namespace std {

        template<class A1, class A2>
        ostream& operator<<(ostream& s, vector<A1, A2> const& vec)
        {
            copy(vec.begin(), vec.end(), ostream_iterator<A1>(s, "
"));
            return s;
        }
    }


Which has undefined behavior. You can only add template
specializations to namespace std when they depend on
user-defined types.


Formally true.

On practice it works just fine as long as One Definition Rule
is not violated.


Taking into account all of the code, including that which you
can't see or know about, such as in the implementation of the
library.

In other words, it works just fine as long as you're lucky.

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