Re: g++4.3.2 w/ c++0x: error: no type named ?iterator? in ?class std::unordered_map<...'

From:
"Bo Persson" <bop@gmb.dk>
Newsgroups:
comp.lang.c++
Date:
Sun, 23 Nov 2008 11:00:20 +0100
Message-ID:
<6osnthF56eloU1@mid.individual.net>
Samuel.Hornus@gmail.com wrote:

Hi,
I have a problem with g++ 4.3.2 in -std=c++0x mode.
Here is some code which works fine:

struct My_data
{
 typedef std::map<Key, My_data, Compare> My_Map; (***)
 typedef typename My_map::iterator My_iterator;
 // data members
 My_iterator cousin_;
};
typedef std::map<Key, My_data, Compare> My_Map;
My_map Family;

Note, that it uses My_data as the data_value for the std::map type
defined in the My_data struct *itself*.
This works fine. But now I want to change std::map by
std::unordered_map.
So do I, with appropriate hash function and Equality comparator.
But then, g++ 4.3.2 gives me the following error:

error: no type named ?iterator? in ?class std::unordered_map<...'
at line (***). I know this does come from the fact that I'm using
My_data as a template parameter inside the definition of the struct
My_data itself.
But... it did work for std::map... so why shouldn't it work for
unordered_map ?
Is there a workaround ? is this a bug of libstd++ ?
Thank you very much !
sam


It just happened to work for std::map, even though it is not required.

The workaround would possibly be to store a pointer or a reference to
the cousin, instead of an iterator.

Bo Persson

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