Re: Question on iterator. Why is a pointer?

Dear all:

I am reading "Thinking in C++" volume 2, p629, and have a question on
the below code:

......
static void run( ) {

     vector<Task *>::iterator it = tasks.begin( );
     while (it != tasks.end())
          (*it++)->operation( );
}

.....

My question here is: why use (*it++)-> for the iterator it? which
indicate that it is a pointer. But from the defination, I only see
vector<Task *>::iterator it = tasks.begin( );, instead of vector<Task
*>::iterator *it; The vector <Task *> only indicate that the vector
contains <Task *> inside, doesn't mean it is a pointer, if from the
defination above, no pointer * is in front of it.

I believe the book is correct. But what's wrong with my understanding.

Any help for clarifying this will be appreciated.