Re: What is the official way of checking that opening a file succeeded?

From:
Victor Bazarov <v.Abazarov@comAcast.net>
Newsgroups:
comp.lang.c++
Date:
Tue, 24 Feb 2009 12:44:31 -0500
Message-ID:
<go1blv$h4r$1@news.datemas.de>
Juha Nieminen wrote:

  Consider this:

int main()
{
    std::ifstream is("file1");
    if(is.good())
    {
        std::cout << "ok\n";
        std::string line;
        while(std::getline(is, line));
        is.close();
    }


At this point 'is' is in a fail state, most likely, after trying to read
past its end. You need to reset the state. Do

       is.clear();

here.

    is.open("file2");
    if(!is.good())
    {
        std::cout << "failed!\n";
    }
}

  Assume that both files exist and are normally readable. With gcc the
"failed!" output is not triggered, while with MSVC++ 2005 it is
triggered. (errno points to "no error" in this case, so the file was
clearly opened successfully, but the good() bit was not set.)

  I can only assume one of two things. Either

1) good() is *not* the proper way of checking if opening a file
succeeded, or

2) there's a bug in MSVC++ 2005.

  Comments?


See above

V
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