Re: passing virtual member function to templates
g3rc4n@gmail.com wrote:
On Mar 18, 2:17 am, Victor Bazarov <v.Abaza...@comAcast.net> wrote:
thanks got it sussed
"Sussed"? Sorry, English is not my first language.
template<class T, class FUN>
void foo(T& t, FUN f){
Why is 't' a reference? You could just drop the '&' altogether, no?
The code in the function requires 't' to be a dereferenceable entity
(like a pointer or an iterator).
(*t.*f)();
I may have been too quick to dismiss the -> syntax you had before. It's
probably fine if you write
(t->*f)();
because then 't' is required to be a pointer.
}
struct base{
virtual ~base(){}
virtual void say()=0;
};
struct dir : public base{
void say(){
std::cout << "hi" << std::endl;
}
};
void bar(){
base* ptr = new dir;
foo(ptr,&base::say);
}
g++ doesn't like FUN& because it doesn't like base::*&
Well, that does look like a rather funky syntax...
V
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