Re: Copying Few Octets from Vector

From:

Victor Bazarov <v.Abazarov@comAcast.net>

Newsgroups:

comp.lang.c++

Date:

Fri, 10 Apr 2009 09:54:30 -0400

Message-ID:

<grnj2m$3gl$1@news.datemas.de>

smilesonisamal@gmail.com wrote:

On Apr 10, 6:25 pm, Victor Bazarov <v.Abaza...@comAcast.net> wrote:

smilesonisa...@gmail.com wrote:

Hi all,
I am facing difficulty in copying few octets from a vector to a
buffer.

What kind of difficulty?

typedef unsigned char uint8_t;
I have a vector std::vector<uint8_t*> m_Data;
which contains the following octets. I want to copy (30 74 64 230 0 8)
to a buffer. I saw in the web and got code where iterator is used to
copy all the octets not partial elements. How will I retrieve 6 octets
from the vector? I am new to C++ and facing lot of problems in
conversion.

"In conversion"? To and from what?

> I tried a lot but couldnot succeed.Could anybody help me

in this regard?

Yes, we can help. What have you tried? Post your code.

Any example source code will be great help.

Show us yours and we'll show you ours. Oh, and while you're at it,
check out FAQ 5.2, please. You can find the FAQ list here:http://www.parashift.com/c++-faq-lite/

Vector Elements
-------------------------
1 0 94 0 0 2 0 30 74 64 230 0 8 0 69 0 0 48 0 0 0 0 1 17 168 216 146
223 158 3 2
24 0 0 2 7 193 7 193 0 28 81 57 0 0 8 3 10 100 5 0 99 105 115 99 111 0
0 0 146 2
23 158 1

V
--
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Hi,

I have tried and could not succeed.

What exactly isn't working? Did you read the FAQ? If you haven't,
please do, and pay close attention to FAQ 5.8.

std::vector<uint8_t*> m_Data;

unsigned char*
GetData(unsigned long octetOffset)
{

unsigned long bufferLength = m_Data.size() - octetOffset;
uchar* buffer = new uchar[bufferLength];

   // Copy the packet data buffer
  const_iterator it = m_Data.begin() + octetOffset;

   int octet = 0;
   for (; it != m_Data.end(); ++it, ++octet)
      buffer[octet] = *it;

   return buffer;

}

V
--
Please remove capital 'A's when replying by e-mail
I do not respond to top-posted replies, please don't ask

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