Re: Just want to make sure...
On Apr 28, 9:20 pm, Noah Roberts <n...@nowhere.com> wrote:
Drew Lawson wrote:
In article <49f75393$0$2709$cc2e3...@news.uslec.net>
Noah Roberts <n...@nowhere.com> writes:
#include <iostream>
#include <memory>
struct T {};
std::auto_ptr<T> f() { return new T; }
int main()
{
std::auto_ptr<T> at = f();
std::cout << "test\n";
std::cin.get();
}
The above code should compile and work fine, no? I should
not be getting a crash due to doubly deleted memory
segments...right?
I've used auto_ptr, but never as a return type. I think you
really want to return a T* and store it in auto_ptr.
Otherwise 'at' may be a copy of a temporary auto_ptr.
And that would be bad.
It shouldn't be. The temporary should be assigned to at,
which then holds the ptr while the original temp holds 0.
That's the way VC++ implements it, and that corresponds
literally to what the standard says to do. Practically,
however... is there a possibility of the auto_ptr_ref outliving
the original auto_ptr used to create it? If so, there could be
a serious problem. G++ avoids this by dropping ownership when
the auto_ptr_ref is created. Which of course, will cause a
memory leak if the auto_ptr_ref isn't ultimately used to craete
an auto_ptr.
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