Re: Weird behaviour from std::list<>::reverse_iterator

From:
Victor Bazarov <v.Abazarov@comAcast.net>
Newsgroups:
comp.lang.c++
Date:
Mon, 24 Aug 2009 13:34:10 -0400
Message-ID:
<h6uiuj$9ea$1@news.datemas.de>
Rune Allnor wrote:

(Sorry if this question appears in two posts)

I have a list of size_t objects, the numbers 0, 1 and 2,
that are referenced by three ..::reverse_iterators. When I
erase the middle iterator, the item referenced by the argument
to list.erase() remains, while some other item has been deleted.

As far as I can see, this behaviour is not correct. The screen
dump below explains what was actually done, and compare it
to what I naively would expect to see. I also ran a similar test
with std::list<>::iterator types, and in that case the outcome
was as expected. So there is something weird about the
reverse_iterators.

Any opinions about what the cause might be?


Well, you think you're erasing the value '1' but to know what value
you're erasing you need to print out 'middle.base()' that you're using
to erase something from the list.

Your misconception is that *middle == *(middle.base()). It isn't. The
reverse iterator's 'base' iterator points to a different value in the
container. At least IME.

I'm using VS2008.


I don't believe it should matter.

Rune

/*****************************************************************/
Reverse iterator 'start' refers to value 0 - expected value 0.
Reverse iterator 'middle' refers to value 1 - expected value 1.
Reverse iterator 'tail' refers to value 2 - expected value 2.

Value referenced by reverse iterator 'middle' has been erased
Reverse iterator 'start' refers to value 0 - expected value 0.
Reverse iterator 'tail' refers to value 1 - expected value 2.

1st item in list: 0 - expected value 0.
2nd item in list: 1 - expected value 2.
/*****************************************************************/

#include <list>
#include <iostream>

int main()
{
    std::list<size_t> list;

    for (int n=0;n<3;++n)
        list.push_back(n);

    std::list<size_t>::reverse_iterator start = list.rbegin();
    std::list<size_t>::reverse_iterator tail = start++;
    std::list<size_t>::reverse_iterator middle = start++;
    std::cout << "Reverse iterator 'start' refers to value " << *start
        << " - expected value 0."<< std::endl;
    std::cout << "Reverse iterator 'middle' refers to value " << *middle
        << " - expected value 1."<< std::endl;
    std::cout << "Reverse iterator 'tail' refers to value " << *tail
        << " - expected value 2."<< std::endl;

    // Erase middle item from list.
    list.erase(middle.base());
    std::cout << std::endl;
    std::cout << "Value referenced by reverse iterator 'middle' has been
erased" << std::endl;
    std::cout << "Reverse iterator 'start' refers to value " << *start
        << " - expected value 0." << std::endl;
    std::cout << "Reverse iterator 'tail' refers to value " << *tail
        << " - expected value 2." << std::endl;
    std::cout << std::endl;

    std::list<size_t>::iterator i = list.begin();
    std::cout << "1st item in list: " << *i
        << " - expected value 0." << std::endl;
    ++i;
    std::cout << "2nd item in list: " << *i
        << " - expected value 2." << std::endl;

    return 0;
}


V
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