Re: Run-time-checking whether a pure virtual function has been implemented

From:
Victor Bazarov <v.Abazarov@comAcast.net>
Newsgroups:
comp.lang.c++
Date:
Thu, 27 Aug 2009 14:10:43 -0400
Message-ID:
<h76i73$f40$1@news.datemas.de>
Jonathan Lee wrote:

On Aug 27, 8:58 am, Nordl?w <per.nord...@gmail.com> wrote:

Is it possible to do runtime-checks whether a virtual base-class pure
virtual function has been implemented in an inherited class?


If it compiled, it's implemented, no?


No. Using the scope resolution you can explicitly call a pure function
even for the derived class that has a non-pure final overrider. See
elsethread.

For example, the following code does not compile because "the
following virtual functions are pure within 'Derived'".

--Joathan

=======================================
#include <iostream>

class Base {
  public:
    virtual void print() = 0;
    Base* get() { return this; }
};

class Derived : public Base {
  public:
    //void print() { std::cout << "Derived" << std::endl; }
    void saymyname() { std::cout << "Derived" << std::endl; }
};

int main() {
  Derived d;

  return 0;
}


V
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