Re: erase function in vector

From:
Thomas Maeder <maeder@glue.ch>
Newsgroups:
comp.lang.c++.moderated
Date:
Thu, 24 Sep 2009 06:48:45 CST
Message-ID:
<8763b8u69q.fsf@madbox3.site>
Jun <junhufr@gmail.com> writes:

I've a vector of integer 4 4 4 5 9
suppose I deleted 5, i got 4 4 4 9
and sort by decreasing number ordering : 9 4 4 4
but when i output *(vector.end()), it aways show 9


Evaluating the expression *vector.end() has undefined behavior. Any
output is correct, including no output or a crash or your computer
catching fire.

But vector.end() still works when during loop.

vector<int> v;
// initialize
vector<int>::iterator ir = v.begin();
while(ir != v.end()){
   if(*ir == 5)
     ir = v.erase(ir);


A typical implementation will
- copy the value 9 from position 4 to position 3 (that is the position
  that ir refers to in this moment), and
- move v's end marker to one position before what is was before
- *not* do any memory (re)allocations

   else
     ++ir;
}

cout << *v.end() << endl;
sort(v.begin(),v.end(), sortbySize);
cout << *v.end() << endl;


Again: this has undefined behavior.

But it is very plausible that a typical implementation will write 9
because that's the value at the last position before v was shrunk.

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