Re: typedefs and templates

From:

Victor Bazarov <v.Abazarov@comAcast.net>

Newsgroups:

comp.lang.c++

Date:

Mon, 05 Oct 2009 15:57:31 -0400

Message-ID:

<hadj35$hdq$1@news.datemas.de>

kf3cr wrote:

I am including the code that does not compile below. I am curious as to
why this does not compile, and I would appreciate it if anybody knew
where in the c++ standard I could info to better understand this issue.

For the sake of this post I am going to assume that gcc 4.2.1 is better
with the c++ standard than my copy of visual studio 2009 version
9.0.30729.1 SP since gcc gives the error and visual studio compiles it.

gcc Error text:
main.cpp: In member function 'void B<G>::f()':
main.cpp:22: error: expected ';' before 'itr2'

#include <vector>

template <typename T>
class A
{
    public:
        typedef std::vector<int> stuffs;
        typedef stuffs::const_iterator ConstIterator;
};

template <typename G>
class B
{

    public:
        void f(void)

C-ism: omit the 'void' when defining an empty parameter list. Don't put
anything where nothing is expected. Just write

void f()

While it's not an error, it clutters the code with something that is
totally unnecessary.

         {
            A<bool>::ConstIterator itr1; // this is ok

            A<G>::ConstIterator itr2; // Problem here

'ConstIterator' is a dependent name. Turn up the warning level on VC++
or disable the language extensions, and you may see the problem.

The solution is to use 'typename' before the type name:

typename A<G>::ConstIterator itr2;

}
};

int main(void) {return 0;}

V
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