Re: Order of destruction of static members and static objects
James Kanze wrote:
That's often the simplest and most appropriate solution. If
Container is a more general class (e.g. an std::vector), then
you can wrap it in a simple function to ensure the same
behavior. Another solution is to ensure that Container has a
trivial destructor.
How can you implement safely something like this?
// Header file
// -----------
class A
{
static std::vector<int> sharedContainer;
A(const A&);
A& operator=(const A&);
public:
A();
~A();
};
// Source file
// -----------
std::vector<int> A::sharedContainer;
A::A() { sharedContainer.push_back(0); }
A::~A() { sharedContainer.pop_back(); }
If somewhere else you have something like:
namespace { A a; }
then the constructor might be accessing an unconstructed std::vector,
and the destructor might be accessing a destroyed std::vector.
Construction safety could be ensured by changing the container to:
namespace
{
std::vector<int>& sharedContainer()
{
static std::vector<int> container;
return container;
}
}
But does that ensure that it's not accessed after it has been
destroyed? If not, how do you make sure it's not?
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