Re: Automatic function result type adaption depending on arg?

From:
"Alf P. Steinbach" <alfps@start.no>
Newsgroups:
comp.lang.c++
Date:
Mon, 08 Mar 2010 10:50:54 +0100
Message-ID:
<hn2ha4$2lo$1@news.eternal-september.org>
* Anthony Delroy:

On Mar 7, 9:33 am, "Alf P. Steinbach" <al...@start.no> wrote:

I have e.g.

     template< typename T >
     inline typename T::iterator startOf( T& c )
     {
         return c.begin();
     }

     template< typename T >
     inline typename T::const_iterator startOf( T const& c )
     {
         return c.begin();
     }

     template< typename T, Size N >
     inline T* startOf( T (&a)[N] )
     {
         return a;
     }

Types from the standard library use 'iterator' and 'const_iterator', but imagine
some other large set of types TheirOwnWay with e.g. 'Iter' and 'ConstIter', and
that those types are in numeruous different namespaces.

How can the functions above be modified so that it's simple to make them work
also with TheirOwnWay types, e.g. by defining some type trait thing?

I tried the to me "obvious" customization hook, like

     template< typename T >
     inline typename IterTrait<T>::T startOf( T& c ) ...

keeping the last overload above as-is, but this failed spectacularly when
calling startOf(a) where a is a raw array.

I'd rather avoid using Boost enable_if (or any Boost dependency).


Is there some reason not to overload startOf as below? This is
similar to the way I tend to add operator<<()...

Cheers,
Tony

#include <cassert>
#include <iostream>
#include <vector>

template< typename T >
inline typename T::iterator startOf( T& c )
{
    std::cout << "startOf(T& c) returning T::iterator\n";
    return c.begin();
}

template< typename T >
inline typename T::const_iterator startOf( T const& c )
{
    std::cout << "startOf(const T& c) returning T::const_iterator\n";
    return c.begin();
}

template< typename T, size_t N >
inline T* startOf( T (&a)[N] )
{
    std::cout << "startOf(T (&a)[N]) returning a\n";
    return a;
}

struct X
{
    typedef const int* Const_Iterator;
    typedef int* Iterator;

    X(int a, int b) { a_[0] = a; a_[1] = b; }

    Const_Iterator first() const { return a_; }
    Iterator first() { return a_; }

    friend Const_Iterator startOf(const X& x) {
        std::cout << "startOf(const X&) returning X::Const_Iterator
\n";
        return x.first();
    }
    friend Iterator startOf(X& x) {
        std::cout << "startOf(X&) returning X::Iterator\n";
        return x.first();
    }

    int a_[2];
};

int main()
{
    std::vector<int> i;
    i.push_back(4);
    i.push_back(10);
    assert(*startOf(i) == 4);
    const std::vector<int>& ci = i;
    assert(*startOf(ci) == 4);

    int ai[2] = { 4, 10 };
    assert(*startOf(ai) == 4);

    X x(4, 10);
    assert(*startOf(x) == 4);
    const X& cx = x;
    assert(*startOf(cx) == 4);
}


Thanks. I was thinking of something that wouldn't require defining each of
'startOf', 'endOf' and 'size' for each class. But if that's what's practically
required then OK.

Cheers,

- Alf

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