Re: argument packs manipulations

From:
=?ISO-8859-1?Q?Daniel_Kr=FCgler?= <daniel.kruegler@googlemail.com>
Newsgroups:
comp.lang.c++.moderated
Date:
Tue, 24 Aug 2010 23:25:45 CST
Message-ID:
<9567e7f2-b4f3-4463-ade0-f6a6a507c7f0@j18g2000yqd.googlegroups.com>
On 24 Aug., 23:04, Marc <marc.gli...@gmail.com> wrote:

First, thanks a lot for this very detailed and useful answer.


You are welcome.

Note that the hom function was later replaced with:

template <class...> struct Last_type; // bug 39653
template <class T,class... U> struct Last_type<T,U...> {
        typedef typename Last_type<U...>::type type;};

template <class T> struct Last_type<T> {
        typedef T type;
};


Occasionally I also found use for the more
general tool:

template<std::size_t I, class...> struct ith;

template<class T, class... Ts>
struct ith<0, T, Ts...> {
  typedef T type;
};

template<std::size_t I, class T, class... Ts>
struct ith<I, T, Ts...> {
  typedef typename ith<I - 1, Ts...>::type type;
};

template <class T> T && last_arg(T && t) {
        return std::forward<T>(t);}

template <class T,class... U>
typename Last_type<U&&...>::type last_arg(T&&, U&&... u)
// bug 44175
//auto last_arg(T&&, U&&... u)
//->decltype(last_arg(std::forward<U>(u)...))
{
        return last_arg(std::forward<U>(u)...);
}


Yes, that should also work. In fact, it is possible
to define a set of free get functions, tuple_element,
and tuple_size for parameter packs (I did that a while
ago). The disadvantage of such an approach is, that
the compiler needs to expand the pack recursively (with
one element less each time). So, I think that forwarding
such a pack once is *in general* the more effective
approach.

One thing though: std::get seems to lose the rvalue-ness of arguments
(not that it's hard to get the i-th type and cast appropriately
afterwards).


Indeed, this is reflected by the following library issue:

http://www.open-std.org/jtc1/sc22/wg21/docs/lwg-active.html#1191

template<class T, int D>
struct VecBase {
  T tab[D];

  template<std::size_t... I, class Tuple>
  VecBase(eq_tag, indices<I...>, Tuple&& t) :
    tab({static_cast<T>(std::get<I>(t))...})
  {
  }


With code like this, do I get a conversion followed by a copy/move, or
can the compiler do the conversion directly into tab[i]? And if I
replace std::get with something more std::forward-like and pass a
temporary to the constructor, do I still stand a chance that tab[i]
may be directly move-initialized from it?


static_cast indeed performs a conversion and may construct a
temporary, see [expr.static.cast]/4. You can get rid of
the static_cast, but that would have the effect that you
couldn't initialize a double array with int values because
narrowing conversions strike back. Assuming that rvalue-
reference overloads of get are provided as described in LWG
issue #1191, you would probably want to replace this by:

   template<std::size_t... I, class Tuple>
   VecBase(eq_tag, indices<I...>, Tuple&& t) :
     tab({static_cast<T>(std::get<I>(std::forward<Tuple>(t)))...})
   {
   }

If you can live without support for int -> double
support, you can remove the static_cast of-course,
but you should test that (when possible). In a more
complicated - but potentially more efficient -
implementation you could type-switch between
using static_cast (e.g. for conversions among
scalar types) and not using so (all other cases).

HTH & Greetings from Bremen,

Daniel Kr?gler

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