Re: Moving elements out of an initializer-list

From:
SG <s.gesemann@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Fri, 17 Sep 2010 02:01:41 -0700 (PDT)
Message-ID:
<c9df1555-4565-4299-85e9-e7ffec89b641@c16g2000vbp.googlegroups.com>
On 16 Sep., 23:42, Johannes Schaub wrote:

SG wrote:

On 16 Sep., 22:24, Johannes Schaub wrote:

[...]
The draft guarantees that the initializer_list refers to that non-const
array, if "T" is nonconstant (by the text you quoted earlier from
8.5.4/4).


How can it guarantee that it refers to a non-const array when at the
same time it specifically allows a compiler to place the objects into
a ROM?


Well as I pointed out in my earlier response, it does not do so. All it has
is a note (!) that it may place it into a ROM when an explicit array may be
placed that way too. A non-const array cannot be placed into ROM so the
initializer_list won't do so either.


By that logic this optimization would only apply in cases where we
have a constructor like this:

  struct X {
    X(std::initializer_list<const double>);
  };
  X x {1,2,3};

(Note the "const double"). I don't believe this is the *intention* of
the draft. From what I can tell the wording is contradictory / worth
improving:

8.5.4/4:

  "An object of type std::initializer_list<E> is constructed from
   an initializer list as if the implementation allocated an array
   of N elements of type E, where N is the number of elements in
   the initializer list. Each element of that array is
   copy-initialized with the corresponding element of the
   initializer list, and the std::initializer_list<E> object is
   constructed to refer to that array. If a narrowing conversion is
   required to initialize any of the elements, the program is
   ill-formed. [ Example:

      struct X {
         X(std::initializer_list<double> v);
      };
      X x{ 1,2,3 };

   The initialization will be implemented in a way roughly
   equivalent to this:

      double __a[3] = {double{1}, double{2}, double{3}};
      X x(std::initializer_list<double>(__a, __a+3));

   assuming that the implementation can construct an
   initializer_list object with a pair of pointers. --end ]"

8.5.4/5:

  "The lifetime of the array is the same as that of the
   initializer_list object. [ Example:

      typedef std::complex<double> cmplx;
      std::vector<cmplx> v1 = { 1, 2, 3 };
      void f() {
         std::vector<cmplx> v2{ 1, 2, 3 };
         std::initializer_list<int> i3 = { 1, 2, 3 };
      }

   For v1 and v2, the initializer_list object and array created for
   { 1, 2, 3 } have full-expression lifetime. For i3, the
   initializer_list object and array have automatic lifetime.
   --end example ] [ Note: The implementation is free to allocate
   the array in read-only memory if an explicit array with the same
   initializer could be so allocated. --end note ]

18.9/2:

  "An object of type initializer_list<E> provides access to an
   array of objects of type const E. [ Note: A pair of pointers or
   a pointer plus a length would be obvious representations for
   initializer_list. initializer_list is used to implement
   initializer lists as specified in 8.5.4. Copying an initializer
   list does not copy the underlying elements. --end note ]"

So, 8.5.4/4 links an initializer_list<E> object to an array of N
elements of type E. 18.9/2 links an initializer_list<E> object to an
array of N elements of type CONST E. Contradiction. Also, I firmly
believe that it is NOT intentional to only allow this ROM optimization
to be used in case E is itself const. I find it much more likely that
someone forgot to add a couple of "const"s in 8.5.4/4.

Cheers!
SG

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