Re: recursive lambda

From:
=?ISO-8859-1?Q?Daniel_Kr=FCgler?= <daniel.kruegler@googlemail.com>
Newsgroups:
comp.lang.c++.moderated
Date:
Thu, 2 Jun 2011 18:28:49 CST
Message-ID:
<is8pss$5ru$1@dont-email.me>
Am 02.06.2011 21:14, schrieb Florian Weimer:

* Sarang:

I was planning to write a recursive version of prime numbers using lambda
but not sure if I can use lambda's recursively:


You need a fixpoint combinator. I tried to write one:

  template<typename F, typename... Args>
  typename std::result_of<F>::type
  fix(F f, Args&&... args)
  {
    auto fix_f = [&](Args&&... args1) -> typename std::result_of<F>::type {
      return f(fix_f, std::forward<Args>(args1)...);
    };
    return fix_f(std::forward<Args>(args)...);
  }
    bool is_prime_r(int num)
  {
    auto prime_rec = [](std::function<int(int, int)> rec,
                        int num, int den) -> bool
      {
        if(den == 1 )
          {
            return true;
          }
        else if( num % den == 0 )
          {
            return false;
          }
        else
          {
            return rec(num, den -1);
          }
      };
    return fix(prime_rec, num, num - 1);
  }

But GCC 4.6 doesn't like it, either:

| error: no matching function for call to 'fix(is_prime_r(int)::<lambda(std::function<int(int, int)>, int, int)>&, int&, int)'
| note: candidate is:
| note: template<class F, class ... Args> typename std::result_of<F>::type fix(F, Args&& ...)

Is the code above supposed to compile with a C++0X compiler?


No, for several reasons:

1) You are using std::result_of incorrectly, you must specify the arguments of the functor F.

2) Within function fix you are using auto as type-specifier in a variable declaration incorrectly, because you are referring to the name of the declared variable (fix_f) within its initializer (7.1.6.4p3 as quoted in my other reply).

HTH && Greetings from Bremen,

Daniel Kr?gler

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