Re: template argument deduction for overloaded predicates
On Nov 6, 6:10 pm, MJanes <max....@googlemail.com> wrote:
{ Your article lacks the context of what it's referring to.
Please include some quoting to establish the context. -mod }
I forgot one thing: of course, regarding your original std::all_of
use case, a simpler solution could be just something like:
struct A {};
struct B {};
bool p(A const&);
bool p(B const&);
template<class Iter, class Pred>
void callP(Iter iter, Pred pred);
void f()
{
std::vector<A> as;
callP( as.begin(), static_cast<bool(*)(A const&)>( p ) );
}
Or better yet:
callP( as.begin(), [](A const& x){return p(x);} );
The difference is that in this case the callP specialization directly
calls your lambda (which can be inlined) and your lambda directly
calls p (which could also be inlined if the definition of p is
available in the same translation unit or you can use LTO) -- as
opposed to an indirect function call via function pointer.
Cheers!
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