Re: Matrices in C++

From:
red floyd <no.spam.here@its.invalid>
Newsgroups:
comp.lang.c++
Date:
Sun, 30 Mar 2014 10:07:35 -0700
Message-ID:
<lh9j0r$105$1@dont-email.me>
On 3/30/2014 7:14 AM, Stefan Ram wrote:

red floyd <no.spam.here@its.invalid> writes:

Other than not reinventing the wheel, which you've discussed,
I'd go with std::array<std::array<T,M>,N> as the data type
I'd also make the data member private, and overload
operator()(int row, int col). But that's just me.


   Does this mean that the outer array holds pointers to the
   inner arrays? AFAIK, a C-array cannot be directly contained
   in another C-array, and ::std::array is just a thin wrapper
   around C-arrays. In this case, wouldn't this make access
   more slow, because all the arrays do not necessarily sit at
   one place in memory but might be distributed in different
   places of memory, while a T[ N, M ] C-array is a single
   region of memory and modern microprocessor architecture
   prefers sequences of accesses to neighboring objects?


No, it means the outer array has members which are arrays.
std::array is not just a "thin wrapper around C-arrays", it is
a first-class object.

Thus, if I have std::array<std::array<int,5>,6> a;

a[0] is a std::array<int 5>, not a pointer to anything.

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