Re: ostream_iterator with map pairs
On 7/25/2014 11:18 AM, Richard wrote:>
[Please do not mail me a copy of your followup]
I must be doing something wrong, but I expected this to compile and work:
#include <algorithm>
#include <iostream>
#include <iterator>
#include <map>
std::ostream& operator<<(
std::ostream& out,
const std::pair<size_t, size_t>& rhs)
{
return out << rhs.first << ", " << rhs.second;
}
int main()
{
std::map<size_t, size_t> m;
for (size_t i = 0; i < 10; ++i)
{
m[i] = 2U*i;
}
std::copy(m.begin(), m.end(),
std::ostream_iterator<const std::pair<size_t, size_t>>(std::cout,
"\n"));
return 0;
}
...but I get a compile error where ostream_iterator is instantiated
both on g++ 4.6.3 and VS 2013.
What am I missing?
It seems that the compiler expects the operator to be found in the 'std'
namespace. It's likely so because both operands are declared in that
namespace. If you place your declaration/definition of the operator<<
in namespace std, it compiles on VC++ 2013 at least.
I am lazy to find the relevant portion of the Standard, it's probably
part of the name lookup.
HTH
V
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