Re: ostream_iterator with map pairs

From:
Victor Bazarov <v.bazarov@comcast.invalid>
Newsgroups:
comp.lang.c++.moderated
Date:
Sat, 26 Jul 2014 11:28:17 CST
Message-ID:
<lqtq7a$ds7$1@dont-email.me>
On 7/25/2014 11:18 AM, Richard wrote:>

[Please do not mail me a copy of your followup]

I must be doing something wrong, but I expected this to compile and work:

#include <algorithm>
#include <iostream>
#include <iterator>
#include <map>

std::ostream& operator<<(
    std::ostream& out,
    const std::pair<size_t, size_t>& rhs)
{
     return out << rhs.first << ", " << rhs.second;
}

int main()
{
     std::map<size_t, size_t> m;

     for (size_t i = 0; i < 10; ++i)
     {
         m[i] = 2U*i;
     }

     std::copy(m.begin(), m.end(),
         std::ostream_iterator<const std::pair<size_t, size_t>>(std::cout,
"\n"));

     return 0;
}

...but I get a compile error where ostream_iterator is instantiated
both on g++ 4.6.3 and VS 2013.

What am I missing?


It seems that the compiler expects the operator to be found in the 'std'
namespace. It's likely so because both operands are declared in that
namespace. If you place your declaration/definition of the operator<<
in namespace std, it compiles on VC++ 2013 at least.

I am lazy to find the relevant portion of the Standard, it's probably
part of the name lookup.

HTH

V
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