Re: set erase of null and nonexistent elements
Anyway, the code below does not make any use of operator(). It uses
std::less<A*>. If that is not specialized in A.h, the remarks below
apply. If it is specialzed, you have to make sure it is a strict total
I meant something else entirely. I was refering to algorithms, such as
find_if where passed predicate, which implemented operator () for
comparison. I assume set uses operator == to locate elements of UDT.
Correct me if am wrong.
You are wrong: std::set<> uses std::less<> to decide whether two elements
are equal. The idea is that a == b can be characterized as neither a < b
nor b < a. In fact, operator== is not used by std::set<> at all.
What does standard or popular implementation dictate of the following
int main(int argc, char **argv)
std::set<A *> aSet;
A *a=new A("NOT HERE")
//here is the list of operations I am
null-op: nullA is not in the set.
null-op: a is not in the set.
//clean up and return
How do standard containers (instantiated with some pointer to user-
defined type) behave in the presence of null pointer?
Well, if we insert a null pointer into a set, wouldn't it cause an
error whenever the container would try to invoke its member.
Yes. Dereferencing a null-pointer is undefined behavior. That, however, does
not imply that you cannot insert the null-pointer into a set. You just have
to make sure that it does not get dereferenced.
Wait, perhaps an std container doesn't do that, hence no errors are to
be seen, then how does find work?
Post code, so that we can discuss find() or find_if() meaningfully. I don't
trust my crystal ball and can only guess what you are looking at.
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