Re: Benchmarks

From:
Keith Thompson <kst-u@mib.org>
Newsgroups:
comp.lang.c,comp.lang.c++
Date:
Thu, 06 Nov 2008 08:21:10 -0800
Message-ID:
<lnfxm4su4p.fsf@nuthaus.mib.org>
s0suk3@gmail.com writes:

The task: Write a program that reads a set of words from standard
input and prints the number of distinct words.

I came across a website that listed a few programs to accomplish this
task: http://unthought.net/c++/c_vs_c++.html (ignore all the language
flaming :-), and thought that all of them did unnecessary operations,
so I wrote my own. But for some reason, my version turned out slower
that ALL of the versions in the website, even though it seems to
perform less operations (yes, I benchmarked them on my own computer).

According to the website, the slowest version is:

#include <set>
#include <string>
#include <iostream>

int main(int argc, char **argv)
{
        // Declare and Initialize some variables
        std::string word;
        std::set<std::string> wordcount;
        // Read words and insert in rb-tree
        while (std::cin >> word) wordcount.insert(word);
        // Print the result
        std::cout << "Words: " << wordcount.size() << std::endl;
        return 0;
}

My version is about 12 times slower than that. It uses lower-level
constructs. Here it is:


[snip]

// Inserts a word into the set if it isn't in the set.
// The passed string is expected to have been allocated with
// a memory allocation function, and it should be considered
// lost after passed to this function.
//
static void
InsertWord(char *aWord)
{
    struct SetNode *node;

    for (node = gSet; node; node = node->next) {
        if (strcmp(node->word, aWord) == 0) {
            free(aWord);
            return;
        }
    }


You represent your set of words as a linked list. You compare each
new word to every word already in the set. The C++ solution uses a
std::set which, if I recall correctly, can do searches and insertions
in O(n log n).

If you re-write this to use a balanced binary tree, such as an AVL
tree, you should get performance similar to the C++ version.

    node = (struct SetNode *) malloc(sizeof(struct SetNode));


Not incorrect, but
    node = malloc(sizeof *node);
would be better.

    if (!node) {
        free(aWord);
        return;
    }


And if malloc fails, you quietly return without doing anything to
handle the error or report it to the user.

[...]

--
Keith Thompson (The_Other_Keith) kst-u@mib.org <http://www.ghoti.net/~kst>
Nokia
"We must do something. This is something. Therefore, we must do this."
    -- Antony Jay and Jonathan Lynn, "Yes Minister"

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