Re: creation of a set of segments, please help

From:
aaragon <alejandro.aragon@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Thu, 13 Nov 2008 15:30:14 -0800 (PST)
Message-ID:
<82118822-541f-4500-91c7-adbb1f06468e@v39g2000pro.googlegroups.com>
On Nov 13, 5:24 pm, SG <s.gesem...@gmail.com> wrote:

On 14 Nov., 00:08, aaragon <alejandro.ara...@gmail.com> wrote:

bool Segment::operator==(const Segment& s)
{ return ((source_ == s.source_ && target_ == s.target_) || (ta=

rget_

== s.source_ && source_ == s.target_)); }


You have to be very careful with comparing doubles -- especially in
case of many geometric algorithms. They work fine on paper but when it
comes to the implementation rounding errors can be a pain in the a**.

Now, I would like to create a set of segments. Of course, the segment
does not have to have duplicates. However, sets are defined by using
operator< which is not defined here.


Right. Anyhow, using points and segments (with doubles as members) as
keys in a set / map might do you harm. In theory you can still work
out a total order. For example: compare Points lexically and store
segments with source<target and compare segments also lexically.

So the question is, how do I create a std::set of segments? Any ideas?


Try to avoid it whenever possible.

Cheers!
SG


Thanks for replying to my post. This is what I came up with since atan
() returns the angle between -pi/2 and pi/2:

struct SegmentSorter {
    bool operator()(const segment_type& s1, const segment_type& s2) const
{
        // compute angle of first segment
        double phi1 = atan((s1.t_.y() - s1.s_.y())/(s1.t_.x() - s1.s_.x()));
        // compute angle of second segment
        double phi2 = atan((s2.t_.y() - s2.s_.y())/(s2.t_.x() - s2.s_.x()));
        return phi1 < phi2;
    }
};

typedef std::set<segment_type, SegmentSorter> segment_set;

What do you think?

aa

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