Re: How to make integer to store 01 instead of 1 ?

From:

gopesh patel <patelgopesh@gmail.com>

Newsgroups:

comp.lang.c++

Date:

Thu, 16 Sep 2010 05:09:40 -0700 (PDT)

Message-ID:

<6ad994bc-0562-4148-b181-0ecc5aa0b1d5@l17g2000vbf.googlegroups.com>

On Sep 16, 1:54 pm, Stuart Golodetz <b...@blah.com> wrote:

gopesh patel wrote:

On Sep 16, 9:12 am, Goran Pusic <gor...@cse-semaphore.com> wrote:

On Sep 16, 12:24 am, gopesh patel <patelgop...@gmail.com> wrote:

Hello all,
I try to store number 01 in integer i like this : int i = 01; =

cout

<< i ;

You do not understand what "int" means. More generally, you do not
understand how numbers are represented in a computer. There is no such
thing as an "int with value 01". There is only value 1. "0" is just
padding that you can add when you turn your "int" into a string of
characters (which happens for you when you "insert" a number into a
stream).

It simply prints 1. What I want is to print 01.
Is it possible ?

Try

#include <iomanip>

cout << setw(2) << setfill('0') << i;

Goran.

Thanks for your answers.
I do understand what integer means and how computer stores it.
I try to be more specific. I dont want to pad 0 to int i in cout. So
iomanip is useless for me.
What I want is when I convert integer 1 to string, the value of string
should become 01 (I want to pad 0 to string after converting it from
int).
Any ideas ?

#include <iomanip>
#include <iostream>
#include <sstream>
#include <string>

int main()
{
        int i = 1;
        std::ostringstream oss;
        oss << std::setw(2) << std::setfill('0') << i;
        std::string s = oss.str();
        std::cout << s << '\n';
        return 0;

}

Cheers,
Stu

Thank you very much Stuart and all who cleared my question.