# Re: sorting through a set of doubles

From:
Pete Becker <pete@versatilecoding.com>
Newsgroups:
comp.lang.c++
Date:
Tue, 29 Jul 2008 07:20:23 -0400
Message-ID:
<2008072907202316807-pete@versatilecodingcom>
On 2008-07-29 03:17:05 -0400, pjb@informatimago.com (Pascal J.
Bourguignon) said:

Pete Becker <pete@versatilecoding.com> writes:

On 2008-07-28 10:51:31 -0400, pjb@informatimago.com (Pascal
J. Bourguignon) said:

pauldepstein@att.net writes:

Suppose x is of the type std::set<double>
I wanted to do a basic sort on x so that the elements were in
numerical order, in the sense that an iterator x.begin() would point
to the least element and so on.
My command std::sort(x.begin(), x.end()); generated compiler
errors.
What should I have done?

std::set<double> x;
std::vector<double> y(x.size());
std::copy(x.begin(),x.end(),y.begin());
std::sort(y.begin(),y.end());
Now y is sorted, and *(y.begin()) is the least element.

Funny thing, though: the result is exactly the same if you comment out
the last line.

Yes, it's just me being paranoiac. However, we could add a different
comparator either in std::set<> or in std::sort().

Certainly: if you were solving a different problem you'd probably end
up with a different solution.
--
Pete
Roundhouse Consulting, Ltd. (www.versatilecoding.com) Author of "The
Standard C++ Library Extensions: a Tutorial and Reference
(www.petebecker.com/tr1book)

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