Re: sorting through a set of doubles
On 2008-07-29 03:17:05 -0400, email@example.com (Pascal J.
Pete Becker <firstname.lastname@example.org> writes:
On 2008-07-28 10:51:31 -0400, email@example.com (Pascal
J. Bourguignon) said:
Suppose x is of the type std::set<double>
I wanted to do a basic sort on x so that the elements were in
numerical order, in the sense that an iterator x.begin() would point
to the least element and so on.
My command std::sort(x.begin(), x.end()); generated compiler
What should I have done?
Now y is sorted, and *(y.begin()) is the least element.
Funny thing, though: the result is exactly the same if you comment out
the last line.
Yes, it's just me being paranoiac. However, we could add a different
comparator either in std::set<> or in std::sort().
Certainly: if you were solving a different problem you'd probably end
up with a different solution.
Roundhouse Consulting, Ltd. (www.versatilecoding.com) Author of "The
Standard C++ Library Extensions: a Tutorial and Reference
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