Re: What is the problem with writing singleton in multithreaded enviroment

From:
"Timo Geusch" <tnews@unixconsult.co.uk>
Newsgroups:
comp.lang.c++.moderated
Date:
17 Jan 2007 19:23:58 -0500
Message-ID:
<xn0f1b9u01unwm001@nermal.unixconsult.co.uk>
James Kanze wrote:

Timo Geusch wrote:

Ronen Yacov wrote:

When declaring a singleton, we write:

static CMySingle::instance()
{
        static CMySingle instance;
        return instance;
}


If I interpret your code correctly, this is not a proper singleton.
But I'm just guessing, seeing that the function has no return type.


Well, since he says it's a singleton, I think we can assume that
the return type is CMySingle& (or CMySingle const&). In which
case, it's pretty much one of the consacrated single threaded
versions of a singleton.


Well, the assumption you made was the one I made originally, too, but
after a few too many late nights spent debugging code that "should have
just worked" so figured it may be worth raising this point.

Why should there be a problem in a multithreaded enviroment?


Because there's a potential race condition if/when two threads call
instance() at the same time and thus initialising instance twice.


Maybe. The real problem is that 1) C++ doesn't say anything
about it, because C++ doesn't address threading, 2) Posix (or
other threading standards) doesn't say anything about it,
because they only address C, and there's no equivalent construct
in C, and 3) most compiler writers don't seem to care, and
pretend that the problem doesn't exist.


I have been following those other threads :) but was somehow hoping
that the original author had been also as I didn't really wanted to
insert a massive section of small print at this point.

Given 1) and 2), it's implementation defined. G++ defines it,
and there's no problem. Most other compilers don't, and in the
absence of a concrete guarantee, you have to assume that there
may be a race condition (and actually is if more than one thread
calls the function before construction is completed in many
implementations).


Thanks for writing what I was trying to say - I've certainly been
bitten by compilers that don't offer the guarantee and am a tad too
familiar with it for my own good.

If one thread creates a static object the other threads will
have the same instance (becuase its static).


That's not the problem. The problem is that there is nothing in your
code that prevents instance from being initialised twice, at the
same time.


Which may or may not be a problem, depending on the compiler.

And if there is a problem, how the docuble check locking solves
it?


Without resurrecting the discussion in another thread, locking per
se mostly solves the problem because it provides a mechanism to
serialise the check if the singleton has already been created.

Double checked locking doesn't really apply in your case anyway but
would normally look like this C++-like pseudo code:

foo* bar::get_foo_instance()
{
    if (!foo_instance) {
      lock.aquire();
      if (!foo_instance) [
        foo_instance = new foo;
      }
      lock.release();
    }
}


Except, of course, that this code doesn't work.


That's why it's called pseudo code :).

 foo_instance
can appear non-null before all of the writes in the constructor
are visible in a given thread. In order to make double checked
locking work, it's generally necessary to insert special
assembler instructions (membar, fence, etc.) at critical places.


Agreed, the above example does needs at least two barriers although I'm
tempted to say it needs three (one after the first check, one after the
call to acquire and one before the call to release).

The double check is necessary because in the above code,
foo_instance may have been initialised while the second was waiting
for the lock, This is a performance optimisation as aquiring the
lock is usually a fairly expensive operation and not necessary if
foo_instance is already initialised.


The idea that aquiring a lock is somehow expensive seems to be
widespread, but it is definitly false. Under Solaris, aquiring
a lock costs less than a function call, at least according to
the measurements I made. From discussions in other threads,
this is a general characteristic of Posix locks, and is
apparently true for CriticalSections under Windows as well.


That's why I said "usually" - although with hindsight I should probably
have written "depending on the type of lock". I've seen the above code
written under Windows using a Windows mutex instead of a
CriticalSection more than once and in that case the double-checked
approach certainly made a difference in performance. Although I'd have
to agree that it would be a valid design question as to why the
instance of a singleton would be requested so often that the lock would
actually show up in the profiler output.

Aquiring a lock is only expensive if someone else is holding it,
and this will only be the case, statistically, if someone holds
the lock for a significant amount of time.


IME it's one of two - either the lock being held for a significant
amount of time or the lock being aquired and release very frequently.

--
The lone C++ coder's blog: http://www.bsdninjas.co.uk/codeblog/

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