Re: newbie question on singleton class

From:
James Kanze <james.kanze@gmail.com>
Newsgroups:
comp.lang.c++
Date:
13 May 2007 04:01:49 -0700
Message-ID:
<1179054109.916382.250090@w5g2000hsg.googlegroups.com>
On May 13, 2:11 am, Gianni Mariani <gi3nos...@mariani.ws> wrote:

On May 12, 11:53 pm, pauldepst...@att.net wrote:

I liked this article by Danny Kalev on the singleton design
class:http://gethelp.devx.com/techtips/cpp_pro/10min/10min0200.asp

However I was confused by this:

QUOTE BEGINS HERE
The class's implementation looks like this:

  Singleton* Singleton::pinstance = 0;// initialize pointer
  Singleton* Singleton::Instance ()
  {
    if (pinstance == 0) // is it the first call?
    {
      pinstance = new Singleton; // create sole instance
    }
    return pinstance; // address of sole instance
  }


A much easier way to write this is:

   Singleton* Singleton::Instance ()
  {
      static Singleton* pinstance = new Singleton;
      return pinstance; // address of sole instance
  }

This will also generate thread safe code on some compilers.
...


So it is claimed. In fact, I only know of one compiler that
even tries, and it fails on my most important target (Solaris on
Sparc).

In practice, what I usually do is to leave the instance variable
outside of the function (more often in an anonymous namespace
than as a static member), and write something like:

    Singleton* ourInstance = Singleton::instance() ;

This ensures (in practice, anyway) that the Singleton::instance
function is called before entering main, and thus before I've
created any threads. And once the pointer is non-null, it is
never modified, so (at least according to Posix), there is no
longer any need to protect accesses. (Note that this code is a
little tricky, since it counts on zero initialization.)

So I would have thought that Singleton* Singleton::pinstance = 0;
violates private access.


The initialization expression is in the scope of the class.


And doesn't access any private variables anyway:-).

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