Re: Could this class be treated as Singleton class

From:
Bart van Ingen Schenau <bart@ingen.ddns.info>
Newsgroups:
comp.lang.c++.moderated
Date:
Wed, 21 Nov 2007 14:53:25 CST
Message-ID:
<33218594.XonWH2YVtg@ingen.ddns.info>
Raman wrote:

Hi All,
I am new to the c++ programming.... lately I came to know about
singleton class( and various method to create one e.g making ctor
private and exposing an other function to create the only instance).
But I want to know ...can the following class be treated as
singleton ...If not then why ?


No, the class in not an implementation of the Singleton pattern.
There is a very fundamental difference between a class that can only
have one instance, ever, and a class that can have multiple instances,
but each instance is initialised to the value of the first one.

It is the second kind of class that you have created here.

#include<iostream>
using namespace std;
class temp{
static int count;
int test;
static void *ptr;
public:
temp(int t){
if(count==0) {
count++;
test=t;
ptr=(void *)this;/***Save the 1st instance**/
             }
else {
*this=*(temp *)ptr;/***After that return the 1st instance
created----I am not sure what exactly is happening here */


What happens here is that you assign the value of the first (saved)
instance to the current instance.
I think this invokes Undefined Behaviour, because you are assigning to
an object that is still under construction.

}

}
~temp(){ /***I think, no need of delete ptr ass it will be done by
compiler automatically */


You should indeed not invoke delete on ptr, but it would be wise to
cleanup after yourself.

  if (this == ptr)
  {
    count--;
    ptr = NULL;
  }

}

void printVal(){
cout<<"\n Val="<<test<<endl;
}


How about adding some extra members:
  void setVal(int t)
  {
    test = t;
  }
  int getVal()
  {
    return test;
  }

};
int temp::count=0;
void * temp::ptr=NULL;

int main()
{
temp t(10);
t.printVal();
temp t1(15);
t1.printVal(); /**both t and t1 contains 10 in the private data
member temp::test */


  t.setVal(12);
  t1.setVal(42);

  t.printVal();
  t1.printVal(); /** What do they print now? For a true singleton, it
would be the same */
  assert(t.getVal() == t1.getVal()); /* The assertion should hold for a
singleton */

}

Thanks All,
Raman Chalotra


Bart v Ingen Schenau
--
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