Re: static object in a function: what if the constructor throws?

From:
gnuyuva <gnuyuva@gmail.com>
Newsgroups:
comp.lang.c++.moderated
Date:
Fri, 16 May 2008 17:31:24 CST
Message-ID:
<5ec3d80d-bf2c-410b-b126-0fc66aa7a665@m45g2000hsb.googlegroups.com>
On May 16, 2:57 am, Krzysztof Czainski <1czaj...@gmail.com> wrote:

[code]
class Singleton
{
   Singleton(); // may throw
public:
   static Singleton& getInstance()
   {
     static Singleton instance;
     return instance;
   }
//...

};

int main()
{
   try {
     Singleton& s = Singleton::getInstance();
     //...
   }
   catch(...) { /* ... */ }}

[/code]

Is it legal for the static variable constructor to throw? Would it
throw during the first call to getInstance, or earlier, or is it
unspecified when? Maybe someone has some other comments on this
implementation of the Singleton pattern?


Ofcourse, its legal for any function to throw an exception and the
constructor is no special case. Same with the static singleton func.
The exception will be thrown while constructor routine is called.
Singleton implementation are not that simple and funny. Search for
"c++ DCLP" and you can find some interesting stuff.

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