Re: destructor is not getting called for singleton

From:
puppi <fabricio.puppi@gmail.com>
Newsgroups:
comp.lang.c++.moderated
Date:
Fri, 29 Apr 2011 18:20:19 CST
Message-ID:
<31586535-1047-47ac-882c-efa91fea7e99@w9g2000prg.googlegroups.com>
On Apr 28, 11:36 pm, Harry <harimca...@gmail.com> wrote:

Singleton.cpp
--------------
template <class T>
T * Singleton<T>::_instance = 0;

template <class T>
Singleton<T>::Singleton() {}

template <class T>
Singleton<T>::~Singleton()
{
        std::cout<<"Singlton Destructor Called"<<std::endl;
     delete _instance;

}

template <class T>
T& Singleton<T>::instance()
{

     if (!_instance)
        {
                std::cout<<"New object only created once"<<std::endl;
         _instance = new T;
        }
     return *_instance;

}

main.cpp
--------
#include "A.cpp"
int main()
{
   single::instance().test();
   return 0;

}

A.cpp
-----
#include <iostream>
#include <string>
#include <fstream>
#include "Singleton.cpp"

class A
{
public:
    A() { std::cout <<"Constructor A called"<<std::endl;}
    ~A(){ std::cout <<"Destructor A called"<<std::endl;}
    void test(){ std::cout<<"Testing"<<std::endl;}
  };
  typedef Singleton<A> single;

output:
New object only created once
Constructor A called
Testing
--

Hi gurus why the destructor is not getting called for singleton?


Because 'instance' is allocated dynamically. It doesn't "go out of
scope" (in fact, that doesn't even make sense: variables have scope,
memory does not). When the program exits, the allocated memory is
simply returned to the system.

If you want proper destruction, delete it.

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