Re: destructor is not getting called for singleton
On Apr 28, 11:36 pm, Harry <harimca...@gmail.com> wrote:
Singleton.cpp
--------------
template <class T>
T * Singleton<T>::_instance = 0;
template <class T>
Singleton<T>::Singleton() {}
template <class T>
Singleton<T>::~Singleton()
{
std::cout<<"Singlton Destructor Called"<<std::endl;
delete _instance;
}
template <class T>
T& Singleton<T>::instance()
{
if (!_instance)
{
std::cout<<"New object only created once"<<std::endl;
_instance = new T;
}
return *_instance;
}
main.cpp
--------
#include "A.cpp"
int main()
{
single::instance().test();
return 0;
}
A.cpp
-----
#include <iostream>
#include <string>
#include <fstream>
#include "Singleton.cpp"
class A
{
public:
A() { std::cout <<"Constructor A called"<<std::endl;}
~A(){ std::cout <<"Destructor A called"<<std::endl;}
void test(){ std::cout<<"Testing"<<std::endl;}
};
typedef Singleton<A> single;
output:
New object only created once
Constructor A called
Testing
--
Hi gurus why the destructor is not getting called for singleton?
Because 'instance' is allocated dynamically. It doesn't "go out of
scope" (in fact, that doesn't even make sense: variables have scope,
memory does not). When the program exits, the allocated memory is
simply returned to the system.
If you want proper destruction, delete it.
--
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