Re: type traits and element specific functions: design problem
Andy wrote:
I am posting below some dummy code which defines a traits template
class and adds a singe typedef. The typedef refers to some defined
class in the progam - I have defined a few dummy classes for that
purpose. Sorry for using the macro to generate code for the dummy
classes.
I compile this code using:
// --- code start --- file: trait_exesize.cpp --- //
#include <iostream>
#define dummy_class(class_name) struct class_name \ {\
class_name::class_name(){\
std::cout << #class_name" constructed"
<< std::endl;\
}\
\
class_name::~class_name(){\
std::cout << #class_name" destructed"
<< std::endl;\
}\
}
dummy_class(A);
dummy_class(B);
dummy_class(C);
dummy_class(D);
dummy_class(E);
dummy_class(F);
template <int DLG_ID> struct dialog_traits {
typedef int val_t;
};
template <>
struct dialog_traits<1>
{
typedef A val_t;
};
...
int main()
{
/**/dialog_traits<1>::val_t a;
dialog_traits<2>::val_t b;
dialog_traits<3>::val_t c;
dialog_traits<4>::val_t d;
dialog_traits<5>::val_t e;
dialog_traits<6>::val_t f;
dialog_traits<7>::val_t g;
dialog_traits<8>::val_t h;
dialog_traits<9>::val_t i;
dialog_traits<10>::val_t j;
dialog_traits<11>::val_t k;
dialog_traits<12>::val_t l;/**/
return 0;
}
It's the object allocations of variables a-l that require both storage
and code. So eliminating dialog_traits does not make the program any
smaller. In other words, a program with this main() routine:
int main()
{
A a;
B b;
C c;
D d;
E e;
F f;
A g;
B h;
C i;
D j;
E k;
F l;
}
produces an identical program. So the dialog_traits class template
(being effectively a typedef) adds no overhead to this sample program.
The more pertinent issue is why allocate two objects of each class A-F?
These classes really should be implemented singletons (or as some kind
of namespace-scope function) if redundant overhead is to be eliminated.
Greg
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