Re: Socket Buffer

Carl Forsman <>
Fri, 16 Jan 2009 16:29:36 -0800
On Wed, 14 Jan 2009 10:27:44 -0800, "Jim Langston"
<> wrote:

"Carl Forsman" <> wrote in message

I have a socket class that will receive data and print it out like the

When i debug the lpBuffer in VC++, why the lpBuffer has all those
strange data like I and at the end has some more strange data?

The only data i sent to the socket is only this -

but there is alot more strange character in the end, why?

void Sock::OnDataReceived(const LPBYTE lpBuffer, DWORD dwCount)

for (DWORD i = 0; i < dwCount; i++) {
m_bReceiveBuffer[m_nReceiveIndex] = lpBuffer[i];
m_nReceiveIndex = (m_nReceiveIndex + 1) % RECEIVE_BUFFER_SIZE;
cout<< (const char*)m_bReceiveBuffer;


In the data you are outputting the last byte is 9E. That is not 0. cout <<
char* will keep printing characters until it hits a null character, one with
the value 0. Which you didn't provide, so it keeps showing whatever happens
to be in memory after your valid data til it reaches a null char. You are
sending binary data yet trying to output it as character string data.
Unfortunately when I squeeze apples I dont get orange juice.

thanks for the hint!

yes, array must set to 0

and then convert to (const char*) to have the whole string converted.

does convert to (char *) also need to terminate with 0 in array?

otherwise some strange character will show up?

    for (DWORD i = 0; i < dwCount; i++) {
        m_bReceiveBuffer[m_nReceiveIndex] = lpBuffer[i];
        m_nReceiveIndex = (m_nReceiveIndex + 1) %
    // must terminate the array to 0 for the array to convert to
    m_bReceiveBuffer[m_nReceiveIndex] = 0;
    cout<< (const char*)m_bReceiveBuffer;

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