Re: change function
On Sat, 2010-01-30, Larry wrote:
"Larry" <firstname.lastname@example.org> ha scritto nel messaggio
this is what I have figure out so far: (untested)
int Socket::ReceiveBytes(char * buffer, int buffersize)
if(buffersize > 32768)
buffersize = 32768;
u_long arg = 0;
if (ioctlsocket(s_, FIONREAD, &arg) != 0)
if (arg == 0)
if (arg > buffersize)
arg = buffersize;
int rv = recv (s_, temp, arg, 0);
if (rv <= 0)
if (rv == 0)
if (rv > 0)
std::copy(temp, temp + rv, buffer);
Try compiling it with full warnings enabled before posting -- I spot
at least one compile error. Also please indent with more that 1 space
-- 4 is rather universal.
Determine the amount of data which can be read atomically from socket s.
argp points to an unsigned long in which ioctlsocket stores the result. If s
is stream oriented (for example, type SOCK_STREAM), FIONREAD returns an
amount of data which can be read in a single recv; this may or may not be
the same as the total amount of data queued on the socket. If s is message
oriented (for example, type SOCK_DGRAM), FIONREAD returns the size of the
first datagram (message) queued on the socket.
It's not clear if you expect your socket to be stream or datagram. Or
what you intend the function to do. It's unusual, I think, to user the
same high-level function for both.
Adding just a tiny bit of documentation would have helped when
discussing it, a lot.
I don't think it's very common for people to use FIONREAD, by the way.
I think there are better options ... but I don't remember exactly and
it's offtopic here anyway.
So I basically I will recv according to ioctlsocket. if the latter is > then
buffersize I will read buffersize (arg = buffersize) if it's
less...well...be just happy with that...if it's 0 or less don't even bother
copying the buffer and return accordingly.
what about my idea?
One thing I don't understand is the extra copying. You went from a
std::string to a char* of known length, but why not read straight into
// Jorgen Grahn <grahn@ Oo o. . .
\X/ snipabacken.se> O o .