Re: Overloading with templates

From:
"Victor Bazarov" <v.Abazarov@comAcast.net>
Newsgroups:
comp.lang.c++
Date:
Thu, 27 Apr 2006 16:09:10 -0400
Message-ID:
<e2r8d7$6ns$1@news.datemas.de>
mlimber wrote:

Victor Bazarov wrote:

mlimber wrote:

Any ideas why this code:

#include <vector>

using namespace std;

struct Foo
{
  void Bar( int, int, int );

  template<typename T>
  void Bar(
    typename vector<T>::const_iterator,
    typename vector<T>::const_iterator,
    int );
};

void Baz()
{
  Foo foo;
  const vector<int> v( 10u );
  foo.Bar( v.begin(), v.end(), 42 );
}

generates this compile-time error:

"ComeauTest.c", line 20: error: no instance of overloaded function
"Foo::Bar" matches the argument list

The argument types that you used are: (
 std::vector<int,std::allocator<int>>::const_iterator,
 std::vector<int,std::allocator<int>>::const_iterator,
 int)
object type is: Foo

    foo.Bar( v.begin(), v.end(), 42 );
        ^

I expected the compiler to select the templatized overload.


The compiler cannot deduce that 'T' is 'int' from
vector<int>::const_iterator. It's not one of "deducible contexts".


Can you elaborate and perhaps supply a work-around (other than
explicit qualification, preferably).


Elaborate? Look in the Standard, 14.8.2.4/9, or in the news archives.

Workaround, eh? Try:

....
   template<class I> void Bar(I, I, int);

In that case your 'I' should be 'std::vector<int>::const_iterator', and
you can then extract 'int' from it using 'value_type' or some such.

 #include <vector>
 using namespace std;
 struct Foo
 {
   void Bar( int, int, int );
   template<typename I> void Bar(I, I, int);
 };

 void Baz()
 {
   Foo foo;
   const vector<int> v( 10u );
   foo.Bar( v.begin(), v.end(), 42 );
   foo.Bar( 1,2,3 );
 }

The code above compiles fine, but it's up to you to see if it suits
your purposes.

V
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