Is this the correct way to do this template?

From:
"Jim Langston" <tazmaster@rocketmail.com>
Newsgroups:
comp.lang.c++
Date:
Sat, 3 Jun 2006 10:53:48 -0700
Message-ID:
<O0kgg.39$4l4.36@fe04.lga>
I have a template I call StrmConvert, which uses std::stringstream to
convert from any type to any other type that can be used by stringstring.
This is what it looks like:

template<typename T, typename F > T StrmConvert( F from )
{
    std::stringstream temp;
    temp << from;
    T to = T();
    temp >> to;
    return to;
}

it works well for me, but I find it can be a lot of typing. I have it in a
namespace called jml so I wind up doing things like this:

std::cout << jml::StrmConvert<std::string>( floatvalue );

I find that 99% of the time I'm converting to std::string so I've decided to
specialize it (if that is the right term) this way:

template<typename F> std::string StrmConvert( F from )
{
    return StrmConvert<std::string>( from );
}

and it seems to work. Now I can say:

std::cout << jml::StrmConvert( floatvalue );

because if I don't specify the typename T is uses the std::string. Is this
the right way to do it? It seems to work, but I want to know if there can
be any problems with this. I did this test and it works, I'm just a n00b
when it comes to templates.

#include <string>
#include <iostream>
#include <sstream>

template<typename T, typename F > T StrmConvert( F from )
{
    std::stringstream temp;
    temp << from;
    T to = T();
    temp >> to;
    return to;
}

template<typename F> std::string StrmConvert( F from )
{
    return StrmConvert<std::string>( from );
}

int main ()
{

    std::cout << StrmConvert<std::string>( 123.45 ) << std::endl;
    std::cout << StrmConvert( 123.45 ) << std::endl;

    float MyValue = StrmConvert<float>( "123.456" );
    std::cout << MyValue << std::endl;

    std::string wait;
    std::cin >> wait;
}

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