Re: container traits

From:
"Greg Herlihy" <greghe@pacbell.net>
Newsgroups:
comp.std.c++
Date:
Mon, 4 Sep 2006 21:35:34 CST
Message-ID:
<1157423115.752322.34900@h48g2000cwc.googlegroups.com>
kanze wrote:

Jens Theisen wrote:

Greg Herlihy wrote:

Both compilers should accept this code - there is nothing
undefined about it at all. The tlist_iterator typedef is
neither an explicit instantiation nor a specialization of
std::list::iterator


Do you know where the requirement of list being instantiable
with incomplete T is in the standard? It should be somewhere.


?17.4.3.6/2: "In particular, the effects are undefined in the
following cases: [...] -- if an incomplete type is used as a
template arugment when instantiating a template component."


Declaring an empty, derived class of T would be an obvious
"workaround". There is no question that T is complete in the program
below. But it should just as clear that the program's behavior is
indistinguishable from the original. After all, a program's behavior is
affected soley by the instructions it executes and the data it
processes. Instantiating std::list<T> (or any template class) creates
neither code nor data. And there cannot be undefined behavior when
there is no behavior at all.

    #include <list>

    struct T { int x; };

    template <class Type>
    struct SelfIter : public Type
    {
        SelfIter() : Type() {}

        typename std::list<Type>::iterator mIterator;
    };

    int main()
    {
        SelfIter<T> ti;

        std::list<T> tList;

        // insert ti in list while storing its iterator
        ti.mIterator = tList.insert( tList.begin(), ti);

    }

The code you posted is illegal, and at least one
compiler/library implemenation rejects it.


I would note that gcc's -D_GLIBCXX_CONCEPT_CHECK will reject any
program that so much as declares a std::list<T>. A concept check tests
a template class for its completeness - it does not test a program for
its correctness. In fact, a concept check essentially does nothing more
than declare a complete, explicit instantiation of std::list<T> like
so:

     template class std::list<T>;

and with the same, predictable results. As a test, a concept check is
useful (and is in fact intended only for) a person actually writing a
template class library. For any other type of programming, the types of
"failures" reported - such as the fact that T does not implement either
a < or a == operator are simply not relevant. A program that never
compares or sorts T objects and never calls any method in std::list
that does - has no reason (and certainly no obligation) to overload
those operators in T.

Greg

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