Re: Template specialisation
vl106 wrote:
In an article (dated back to 2003) I read that the following
code should work:
#include <iostream>
class C {};
template <int> void foo () { std::cout << "int foo\n"; }
template <class T> void foo () { std::cout << "generic foo\n"; }
int main () {
foo <C> (); // output: generic foo
foo <int> (); // output: generic foo
return 0;
}
Why isn't foo <int> () called? Is it because template specialisation
actually is
template <> foo <int> ...
Does the article use an outdated syntax no longer supported by
compilers?
template<int> void foo() { }
is a valid template with non-type [unnamed] template argument.
The two templates co-exist peacefully. You can call the "int"
one by specifying an actual *int* (not the type) after the name:
foo<42>();
V
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