Re: Specialising template member functions with templatized parameters - legal?

From:
Alberto Ganesh Barbati <AlbertoBarbati@libero.it>
Newsgroups:
comp.lang.c++.moderated
Date:
16 Oct 2006 08:37:22 -0400
Message-ID:
<TYHYg.4662$uv5.41438@twister1.libero.it>
Karthick ha scritto:

That said, I have tried the following:
Google search for "error C2910" gives the following link:
http://msdn2.microsoft.com/en-us/library/cx7k7hcf.aspx
Among other things, the site says that the "template <>" should be
dropped during specialisation. But trying out:
// >>> Specialised implementation of to
void B::to<0>(othersize<0>::type){ }
// <<<
doesn't work either ("error C2768: 'B::to' : illegal use of explicit
template arguments")


Be careful. That knowledge base article doesn't exactly says what you
think it says. Here's the relevant part, for reference:

----
// C2910c.cpp
// compile with: /c
template <class T> class A {
    void f();
};

template <> class A<int> {
    void f();
};

template <> void A<int>::f() {} // C2910
// try the following line instead
// void A<int>::f(){} // OK
----

The "template<>" must not be put before "void A<int>::f() {}" because
that's *not* a specialization! It can't be a specialization because "f"
is not a template. "A" is the (class) template and can be specialized.
When "A" is specialized, A<int>::f is declared to be a regular member
function, so the specialization syntax is inappropriate while providing
the definition of A<int>::f.

HTH,

Ganesh

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