Re: A template that calls a different function based on the object passed into the template

From:
"Victor Bazarov" <v.Abazarov@comAcast.net>
Newsgroups:
comp.lang.c++.moderated
Date:
11 Jan 2007 05:24:53 -0500
Message-ID:
<eo49mh$anj$1@news.datemas.de>
Ivan Novick wrote:

I need to write a template function that will call a function whose
name will depend on a parameter to the template, but I can't see how
to do it.

So for example:

void ZoomMyType()
{
}
struct MyType
{
};
void ZoomOtherType()
{
}
struct OtherType
{
};

template<? T> // what should ? be
void do_it()
{
    ZoomT();
}

int main(int argc, char**argv)
{
  do_it<MyType>();
  do_it<OtherType>();
  return 0;
}
===========
It can not be a macro, because this do_it will subsequently be used in
a further template.
===========


Take a look at the FAQ (if you haven't yet), section 35. In case it
isn't obvious from there, you can define two specialisations of your
'do_it' template, one on MyType, the other on OtherType and inside
call your ZoomXX function, respectively.

V
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