Re: A template that calls a different function based on the object passed into the template

From:

red floyd <no.spam@here.dude>

Newsgroups:

comp.lang.c++.moderated

Date:

12 Jan 2007 01:51:57 -0500

Message-ID:

<rwAph.107$O02.99@newssvr11.news.prodigy.net>

Ivan Novick wrote:

Ulrich Eckhardt wrote:

Since you give the template just a type, the '?' needs to be 'typename'.
Then, since there is no common implementation for different types, you
should just declare the function template and then provide specialisations
for the types you need.

The point is I need to call ZoomWhatever and Whatever could be any
number of thousands of different types which don't yet exist.

The language feature i am trying to get is a way to construct a
function name to call based upon the Type of the parameter.

template<typename T>
void do_it()
{
ZoomT();
}

If we can't figure out how to munge the string of the template
parameter with Zoom somehow, then how about some sort of traits
solution?
----

A traits solution would also work (see template example in my previous
message)

template<typename T> struct zoom_traits;

template<> struct zoom_traits<int>
{
    static void Zoom();
}

But that's the same as just making Zoom() itself a template.

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