Re: Dependent type in template base class

From:
Carl Barron <cbarron413@adelphia.net>
Newsgroups:
comp.lang.c++.moderated
Date:
12 Jan 2007 05:30:14 -0500
Message-ID:
<110120072247583358%cbarron413@adelphia.net>
In article <eo5dnd$a4j$1@news01.versatel.de>, Stephan Tolksdorf
<andorxor@gmx.de> wrote:

Hi,

I'd like to make the name of a member type in a template base class
directly available to the child class. (I don't want to qualify each
reference to the type with "typename Base<T>::" in order to avoid
extremely ugly code).
I'm currently doing this with an using declaration as in the following
code snippet:

template <typename T>
class base {
     struct param_type { };
     void f(param_type& p) { }
};

template <typename T>
class test : base<T> {
     using typename base<T>::param_type;
     test(param_type& p) { } // GCC doesn't recognize param_type
}


   is
   template <class T>
   class test:public base<T> // is private inheritance really wanted??
   {
      typedef typename base<T>::param_type param_type;
      test(param_type &p);
   };

   any better??

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