Re: Obtaining function signature

From:
Carl Barron <cbarron413@adelphia.net>
Newsgroups:
comp.lang.c++,comp.lang.c++.moderated
Date:
Sat, 10 Feb 2007 02:58:09 CST
Message-ID:
<090220071931161285%cbarron413@adelphia.net>
In article <1171031407.137232.109670@s48g2000cws.googlegroups.com>,
<psujkov@gmail.com> wrote:

Hi everybody,

int f(int a, int b) { return a + b; };
is it possible to obtain this function signature - int (int, int) in
this case - for use in boost::function_traits ?
e.g. std::cout << "f's arity : " << boost::function_traits<*obtaining
signature from f()*>::arity << std::endl;
please no macro solutions - only C++ (Boost MPL maybe could be useful
- but still don't see how)

best regards, Paul Sujkov

  template <class T> struct function_arity;

   template <class R>
   struct function_arity<R()> {static const int value = 0;};

   // for N=1..N_max do
   template <class R,class T1>
   struct function_arity<R(T1)> {static const int value = 1;};

  template <class R,class T1,class T2>
   struct function_arity<R(T1,T2)> {static const int value = 2;};
   // etc.

   boost's preprocessor library can be used to automate this, but
you said no preprocessor stuff.

   using boost function [which uses the preprocessor :)]
   template <class F> struct function_arity
   {
      static const int value = boost::function<F>::arity;
   };
   but tr1::function does not provide this.

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