Re: templates & classes

From:
Alan Johnson <awjcs@yahoo.com>
Newsgroups:
comp.lang.c++
Date:
Thu, 22 Feb 2007 18:21:44 -0800
Message-ID:
<erlj7a$sl1$1@aioe.org>
John Carson wrote:

"chameleon" <cham_gss@hotmail.com> wrote in message
news:MIlDh.3628$J11.63611@twister1.libero.it

O/H Pete Becker ??????:

chameleon wrote:

I have 2 classes with exactly the same members (all static except
dtor/ctor).
Classes have different implementantion in only one static member
function and first class has one more member function.

How can I write this code with templates?
First of all: Thought to write code with templates is correct?


Seems like overkill. Put all the common stuff into a class, and write
two derived classes.

The problem here is that: All common stuff is static members.
I want 2 template instantiations, so, 2 static member instances.

If I derive 2 classes from one, both classes share common static
members.


You can easily work around that with templates. A simple example follows.

template <int n>
class Base
{
    static int x;
public:
    static void Setx(int a_x)
    {
        x = a_x;
    }
    static int Getx()
    {
        return x;
    }
};

template <int n>
int Base<n>::x;

class Derived1: public Base<0>
{
};

class Derived2: public Base<1>
{
};

int main()
{
    Derived1 d1;
    Derived2 d2;

    d1.Setx(1);
    d2.Setx(2);

    cout << "Static member x of d1 is " << d1.Getx() << endl;
    cout << "Static member x of d2 is " << d2.Getx() << endl;

    return 0;
}


Your solution is correct, but requires assigning each derived class a
unique int. You could instead just directly use the derived class as
the template to the base:

template <class Derived>
class Base
{
     static int x;
public:
     static void Setx(int a_x)
     {
         x = a_x;
     }
     static int Getx()
     {
         return x;
     }
};

template <class Derived>
int Base<Derived>::x;

class Derived1: public Base<Derived1>
{
};

class Derived2: public Base<Derived2>
{
};

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