Re: When int meets bool over ==

From:
"Alf P. Steinbach" <alfps@start.no>
Newsgroups:
comp.lang.c++.moderated
Date:
Fri, 2 Mar 2007 16:17:25 CST
Message-ID:
<54r0sgF21t4guU1@mid.individual.net>
* Alf P. Steinbach:

[at least two typos, as follows]


[snip]

Then there is the operator precedence question.
Consider e.g.
  if( a && b == true ) { ... }
which in C++ has very different effect from
  if( a && b ) { ... }


For "different effect" the concrete example should have been

   if( a && b == false ) { ... }

versus

   if( !(a && b) ) { ... }

With 'a' false the former expression yields false,

   false && (b == false) -> false

while the latter expression yields true:

   !(false && b) -> !false -> true

The advice & general reasoning was correct, but the concrete example
was meaningless.

[snip]

A naming scheme that takes this into account:
  template< typename T >
  bool failed( T const& v ) { return !v; }
  template< typename T >
  bool succeeded( T const& v ) { return !!v; }
  ...
  if( failed( f() ) ) { throw std::runtime_error( "f failed" ); }


In the context I wrote this the called function would signal failure
by logical false result. Hence the 'failed' function should have
double (or no) negation and the 'succeeded' function single negation.

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