Re: Why the compiler complains that it can not find a match?
Note Myself wrote:
Today I wanted to solve an problem: I need to find out in the code if
the iterator passed is a st::vector<T>::iterator, or
std::vector<T>::reverse_iterator. I spent a lot of time tweaking a
template function which is suppose to sovle the issue -
template<typename T>
bool IsForwardIterator(typename T::iterator)
{ return true; }
template<typename T>
bool IsForwardIterator(typename T::reverse_iterator)
{ return false; }
vector<int> vec;
--> bool bFlag = IsForwardIterator(vec.begin());
--> bFlag = IsForwardIterator(vec.rbegin());
The compiler (VC 7.1) complains that it can not locate the overloaded
function.
What might be wrong.
A member type (or a typedef) is not a deducible context for the template.
The compiler is not required to figure out that 'T' is 'vector<int>' if
you supply to it 'vector<int>::iterator'.
BTW, I solve the problem using typeid function.
But it is irrelevant now.
It may not be good enough. Read about type traits. The header
<iterator> contains 'std::iterator_traits' template which can serve
you with the necessary information.
BTW, both 'iterator' and 'reverse_iterator' are Forward iterators
(for a vector they are actually of RandomAccess kind). I think you
may be misunderstanding the meaning of the term "forward iterator".
V
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